9t^2/3+24t^1/3=-16

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Solution for 9t^2/3+24t^1/3=-16 equation: 


t in (-oo:+oo)

(9*t^2)/3+(24*t^1)/3 = -16 // + 16

(9*t^2)/3+(24*t^1)/3+16 = 0

(9*t^2)/3+(24*t)/3+16 = 0

3*t^2+8*t+16 = 0

DELTA = 8^2-(3*4*16)

DELTA = -128

DELTA < 0

t belongs to the empty set

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